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New Geeks on the Block / Re: Elo peeps
« on: September 28, 2011, 03:44:23 PM »
that is it
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New Geeks on the Block / Re: Elo peeps« on: September 28, 2011, 03:43:50 PM »
i see....
so computer is turned into couch forts then ? well im not bothered...im tired, annoyed and worried.... so i will log out and try to do what i can, in the time i have...which isn't much. sorry that went on, didnt want it to, but it did. well you learn something new everyday huh peace mbx 3
New Geeks on the Block / Re: Elo peeps« on: September 28, 2011, 03:20:30 PM »
Aaahh it doesnt matter, i cant be bothered with it now...
i have checked wikipedia etc but that just makes it more complicated as it brings in other formulas that are not even in the course books. i have thoroughly scanned through my book back to front and front to back....but there isnt a formula for this type of question... and usually to answer a question like this, i need an example, so then i know how to do it, otherwise i would never have asked.... haha well hes too busy doing his own thing....he just does this for the fun, as no doubt many do.... thanks for the luck i really will need it... and by the way i do not love couch 'forts' as one of your members so eloquently edited.... i will let you know how it goes.....if it goes. mb 4
New Geeks on the Block / Re: Elo peeps« on: September 28, 2011, 02:58:05 PM »Well I'd warn your Mom that your boyfriend plans to impregnate her. well that aint never gonna happen.... 5
New Geeks on the Block / Re: Elo peeps« on: September 28, 2011, 02:57:30 PM »Now, see? That's funny! well it aint funny for me....so glad it made you laugh like i said all i wanted was a bit of help, or someone to say hey cant help, but try here.... and soz i dint intro before hand i was and still am in panic mode, this assignment is due mora at midday....so i aint got long but genuinely thanks for the offer to stay.... mb 6
New Geeks on the Block / Re: Elo peeps« on: September 28, 2011, 02:47:58 PM »By the way, I AM going to ban redrabbit's IP address. ok jesus christ it was my boyfriend ok, thats what he does, hes a twat ALL I WANTED WAS A BIT OF HELP..... sorry for asking in the first place... do whatever u feel necessary take care mb 7
New Geeks on the Block / Re: Elo peeps« on: September 28, 2011, 02:33:08 PM »No problem. nah not that im aware of ! see post in my other thread...peeps steal my internet... mbx 8
New Geeks on the Block / Elo peeps« on: September 28, 2011, 02:28:22 PM »
Hi peeps of the geekery
i realise that before asking a question in the Homework Help section, i did not introduce myself.... so apologies for that...and here goes.... I'm moon_bear and i love learning bout computers, ive learnt a helluva lot the last 6 months...doing a difficult uni course at the moment....and i do like a bit of gaming over the long ass winter times and am brain dead at the mo, so sorry no witty comments.... but maybe later ^^ take care all and soz bout the no intro before posting =] mbx 9
Homework Help / How to work out the volume occupied by the gaseous products?« on: September 28, 2011, 09:30:30 AM »
Hi there =]
Was just wondering if anyone could help me with this question, my brain is a bit mushy as have been at this for well over a few hours.... I'm not too sure how to go about it....do i find out the RAM of each of the gases and then using the Avogadro hypothesis, work it out from that ? As in doing that the answer will need more than 3 significant figures....so i must be doing something wrong !! Any help with this would be super massively appreciated !! =D Thanks peeps moonbearx C3H5 (NO3)3 (l) + 3H2O (l) decomposes rapidly to produce nitrogen, carbon dioxide, water vapour, oxygen and heat energy according to Reaction 2, with an energy change known as the enthalpy of decomposition. The temperature of this reaction can exceed 5000 °C. Reaction 2; 4C3H5(NO3)3 (l) = 12CO2 (g) + 10H2O(g) + 6N2 (g) + O2 (g) + heat Calculate the volume occupied by the gaseous products from the complete decomposition of 4 moles of C3H5 (NO3)3 (l) + 3H2O (l), as shown in Reaction 2, when cooled to 25 °C and at atmospheric pressure. Express your answer to three significant figures, and explain your reasoning.
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